| | ::Others:: Help in Math? :3 |  |
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Sayumi
Posts : 445
Join date : 2012-01-28
Age : 25
Location : Cavite, Philippines ♥~♥~♥~♥~♥~♥~♥~♥~♥~♥~♥~♥~♥ NOTE: I'm actually a 13-year old Grade 9 student!! ~^^~
|  Subject: ::Others:: Help in Math? :3  Mon Jul 09, 2012 9:49 am | |
| So ~ just a very simple thing..... I need a math formula. A formula that a grade 8th student can understand (which is me xDD) You can give me anything but slope formula, area, perimeter, circumference, percentage/base/rate, and distance/velocity I hope to get some from you girls ><  | |
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kiri
Posts : 306
Join date : 2012-01-22
Age : 29
Location : Toronto, Canada
| | Subject: Re: ::Others:: Help in Math? :3 Mon Jul 09, 2012 10:59 am | |
| the Pythagorean theorem: a^2+b^2=c^2
algebra: (a+b)^2= a^2+2ab+b^2 (a-b)^2= a^2-2ab+b^2
for arithmetic sequence(even though i learnt these in canada this year..but i knew the formula since grade 3):
# of terms: (last# -1st#)/difference+1
sum of total terms: ((last# +1st#) * # of terms)/2
the basic algebra ones i'm sure you know them already...i can't think of anything easy on top of my head..i'm using formulas everyday, but i'm not sure you can understand or not. ask me if you need anything | |
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Icchan
Posts : 491
Join date : 2012-01-22
Age : 26
Location : Toronto, Canada
| | Subject: Re: ::Others:: Help in Math? :3 Mon Jul 09, 2012 3:21 pm | |
| God, I forgot all of this once school was finished =w= I seriously don't fit being a 9th grader, LOLOLOLOL... gomen sayumin!!
WAIT. You're in 8th grade??? oAo woah. | |
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kiri
Posts : 306
Join date : 2012-01-22
Age : 29
Location : Toronto, Canada
| | Subject: Re: ::Others:: Help in Math? :3 Mon Jul 09, 2012 10:24 pm | |
| - Icchan wrote:
- God, I forgot all of this once school was finished =w= I seriously don't fit being a 9th grader, LOLOLOLOL... gomen sayumin!!
WAIT. You're in 8th grade??? oAo woah. don't worry about that...when you get to grade 9, you will learn everything again | |
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Ji hyun
Posts : 204
Join date : 2012-01-22
Age : 28
| | Subject: Re: ::Others:: Help in Math? :3 Tue Jul 10, 2012 1:54 am | |
| I'm a senior and I don't remember any of that! LOL! We don't use them in my math class owo | |
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Sayumi
Posts : 445
Join date : 2012-01-28
Age : 25
Location : Cavite, Philippines ♥~♥~♥~♥~♥~♥~♥~♥~♥~♥~♥~♥~♥ NOTE: I'm actually a 13-year old Grade 9 student!! ~^^~
| | Subject: Re: ::Others:: Help in Math? :3 Tue Jul 10, 2012 8:08 am | |
| Thank you Kiri!  (but I think Pythagorean theorem is too advanced x3) When I graduate, I totally forget the things I hate  BTW, I'll also ask if I did a correct thing on this ↓ - Spoiler:
_______Base____Rate____Percentage
4%_______x_______0.04_______0.04x
8%_______y_______0.08_______0.08y
Total___$90000_____0.12______$6,400
___________________________________________________________
1st equation → x + y = $90,000
2nd equation → 0.04x + 0.08y = $6,400
___________________________________________________________
0.04x + 0.08y = $6,400
0.04y + 0.08y = $6,400
0.12y = $6,400
0.12____ 0.12
y = $6,400
____0.12
y= $53,333
x + y = $90,000
x = $90,000 - y
x = $90,000 - ($53,333)
x = $36,667
The table is correct. I'm just not sure if I did the correct thing on step 2 & 3 | |
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kiri
Posts : 306
Join date : 2012-01-22
Age : 29
Location : Toronto, Canada
| | Subject: Re: ::Others:: Help in Math? :3 Tue Jul 10, 2012 9:23 am | |
| sayumi~~your answer doesn't seem right..here's my way of solving this question just tell me if you need me to explain anything in details - Spoiler:
1st equation → x + y = $90,000
2nd equation → 0.04x + 0.08y = $6,400
0.04x + 0.08y = $6,400
4x + 8y = $640,000 (times everything by 100)
x + 2y = $160,000 (devide everything by 4) → 3rd equation
using elimination
3rd equation - 1st equation = (x + 2y)-(x+y) =y
= 160,000-90,000=70,000=y
using substitution
sub y=70,000 into the 1st equation
x+70,000=90,000
x=20,000
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Icchan
Posts : 491
Join date : 2012-01-22
Age : 26
Location : Toronto, Canada
| | Subject: Re: ::Others:: Help in Math? :3 Tue Jul 10, 2012 3:00 pm | |
| ;A; It all looks like gibberish to mee.... ahh fufufufufufu!
EDIT: nvm, I see how it's done. xD | |
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Sayumi
Posts : 445
Join date : 2012-01-28
Age : 25
Location : Cavite, Philippines ♥~♥~♥~♥~♥~♥~♥~♥~♥~♥~♥~♥~♥ NOTE: I'm actually a 13-year old Grade 9 student!! ~^^~
| | Subject: Re: ::Others:: Help in Math? :3 Wed Jul 11, 2012 8:50 am | |
| @Icchan - Last year, I REALLY DID NOT study on Math  I only know the basics  >< @kiri - you're right ~~ xDD 70,000 + 20,000 = 90,000 How baaka I am xDD Arigatou!  | |
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kiri
Posts : 306
Join date : 2012-01-22
Age : 29
Location : Toronto, Canada
| | Subject: Re: ::Others:: Help in Math? :3 Wed Jul 11, 2012 10:15 am | |
| - Sayumi wrote:
- @Icchan - Last year, I REALLY DID NOT study on Math I only know the basics ><
@kiri - you're right ~~ xDD 70,000 + 20,000 = 90,000 How baaka I am xDD Arigatou! ask me if you have any questions on math. i'm happy to answer them~~~ tips on doing math: think in different ways..always seek for other ways of solving one question. don't give up easily always check your answer | |
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Sayumi
Posts : 445
Join date : 2012-01-28
Age : 25
Location : Cavite, Philippines ♥~♥~♥~♥~♥~♥~♥~♥~♥~♥~♥~♥~♥ NOTE: I'm actually a 13-year old Grade 9 student!! ~^^~
| | Subject: Re: ::Others:: Help in Math? :3 Thu Jul 12, 2012 8:51 am | |
| - kiri wrote:
- ask me if you have any questions on math. i'm happy to answer them~~~
tips on doing math:
think in different ways..always seek for other ways of solving one question.
don't give up easily
always check your answer Arigatou ~~~~~!  I'm actually having problems solving a problem on my own, sometimes, I need a guide (what I do is do the same steps and just change the given numbers & variables ><  ) | |
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kiri
Posts : 306
Join date : 2012-01-22
Age : 29
Location : Toronto, Canada
| | Subject: Re: ::Others:: Help in Math? :3 Thu Jul 12, 2012 10:23 am | |
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Sayumi
Posts : 445
Join date : 2012-01-28
Age : 25
Location : Cavite, Philippines ♥~♥~♥~♥~♥~♥~♥~♥~♥~♥~♥~♥~♥ NOTE: I'm actually a 13-year old Grade 9 student!! ~^^~
| | Subject: Re: ::Others:: Help in Math? :3 Fri Jul 13, 2012 4:54 am | |
| Aaaaa ~ can I ask again?? xDD My classmate gave me a problem. He said he'll not help with our group project if I don't solve this  : Problem: The sum of the digits of a two-digit number is 12. If the digits are reversed, the new number is 18 more than the original number. Find the original number.
I started with this ↓x + y = 12 → 1st eq. y + x = 18 + 12 → 2nd eq. _______________________________________ y = -x + 12 y + x = 30 → 3rd eq. _______________________________________ Then, I can't get the correct answer but I did was... ↓-x + 12 - x = 30 -x + x = 30 - 12 x = 18y = -18 + 12 y = -6 | |
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kiri
Posts : 306
Join date : 2012-01-22
Age : 29
Location : Toronto, Canada
| | Subject: Re: ::Others:: Help in Math? :3 Fri Jul 13, 2012 5:23 am | |
| ahh this question is similar to the previous one but not exactly the same - Spoiler:
let me give u an example before i start doing the question
the number "29"---unit digit is 9 and 10th digit is 2. if you want to get 29 from 9 and 2, what you need to do is 9+2*10=29
once you get this, the question becomes soooo easy.
let x represents the unit digit and y represents the 10th digit
so the number you want is
10y+x
if the digit reversed, that means the unit digit is y and the 10th digit is y
10x+y
and is given that the new number is 18 greater than the old one, so the equation is:
10y+x+18=10x+y
9y-9x=-18 (move all the letters to the left and the number to the right)
y-x=-2 (divide everything by 9)-----equation1
x + y = 12 -----equation 2 (you got this one coreect)
last step, use elimination equation 2-equation1
(x+y)-(y-x)=12-(-2)
2x=14
x=7
using substitution
x+y=12
7+y=12
y=5
so the number is 7+5*10=57
we can check, if the number is 57, the reversed one will be 75.
57+18=75
hope you can understand what i'm saying (excuse all my grammar mistakes><) | |
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